![]() ![]() In MATLAB, you have to use a function handle because MATLAB attempts to execute a function even if you omit the (). # Or pass a lambda function to the other function For example: plt.plot(np.random.rand(20), label'Random 1') plt.plot(np.random.rand(20), label'Random 2') plt.plot(np.random.rand(20), label'Hidden label') plt. ![]() ![]() # Now pass the function to another function directly If you start your label for a plot item with an underscore ( ) then that item will be hidden from the legend. Lambda_square_and_add = lambda x: x**2 + 1 # Create a lambda function which does the same thing. # Function which accepts a function as an input In python, if you don't append the () to the end of the function, it doesn't execute the function and instead yields the function object which can then be passed to another function. A string starting with an underscore is the default label for all artists, so calling Axes.legend without any arguments and without setting the labels manually will result in no legend being drawn. Regardless, assuming that you use them correctly, a function handle in MATLAB is functionally equivalent to using either a lambda or function object as an input argument in Python. The second comment seemed to interpret this to mean that the first commenter thought that you couldn't do this in Python and responded to state that you can use either a lambda or pass the function directly. Markers are automatically accurate In addition, Matplotlib also reflects the different markers in the chart. But that's not the case here since the legend overlaps with one of the dots. Usually, it also places the legend in a good place. The first comment seems to simply reiterate the idea that you can pass a MATLAB function handle as an argument (although the answer didn't state anything that would make me think otherwise). By default, Matplotlib automatically generates a legend that correctly reflects the colors and labels we passed. ![]()
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